Is the result of u × u = 0 perpendicular to both operands?
Yes, because 0 · u = 0, which means that they are perpendicular.
(Recall that by definition, the vector 0 is perpendicular to every vector.)
What about u × 0 ? The magnitude |u||0| sin θ is zero, and the result is a vector, so:
u × 0 = 0 × u = 0
Now, consider (ku) × v. Plug into the formula for the magnitude, |u||v| sin θ, see what you get.
What is (ku) × v ?