Answer:

1  3  5

Just after "5" is printed, the NEXT ODD statement will change ODD from 5 to 7. But 7 is GREATER THAN the ending value 5, so the loop ends.

The Program Illustrated

Here is the program with a picture of how it works. The numbers under "time" show the changing values in ODD.

                            time -->
                            
FOR ODD = 1 TO 5 STEP 2     1       3       5       7 <-- exceeds the limit, 5,   
  PRINT ODD;                  1       3       5            so the loop stops
NEXT ODD                        3       5       7
'
END

This is a little bit confusing. Notice that ODD starts out at 1 and counts up by two. At the end, the NEXT ODD changes ODD to 7, but when this happens the loop is exited because 7 is GREATER THAN the endingValue 5.

QUESTION 7:

Here is a new version of the program (the endingValue has been changed). What does this program print?

FOR ODD = 1 TO 9 STEP 2
  PRINT ODD;
NEXT ODD
'
END