Escaping Metacharacters in a Regular Expression

Question

Say that you want the regular expression \[dog\] which literaly matches the seven characers: \[dog\]

Write the code that puts those characters into a String:

String regex =  ;

String target = "[dog]";

if ( target.matches( regex ) )
  System.out.println("Not so easy, is it?");

Answer 1

String test = "\"This is a backslash \\\", she said.";
System.out.print( test );

"This is a backslash \", she said.

The first " delimits the string, but is not part of the actual string.
The first backslash escapes the " that is the first character of the string.
The next two backslashes mean you want a single backslash included in the string.
The final backslash (immediately following those two) escapes the " that follows it, so that " is part of the string
The final " delimits the string, but is not part of the actual string.