Say that x is very close to n0.5.
What do you think will be the value of n/(x*x)?
It should be very close to 1.0
But due to the lack of precision with floating point, the best we can
hope for is to calculate an x such that:
0.999999 < n/(x*x) < 1.00001
The left and the right bound in the above have 6 decimal digits of precision. If 1.00000 is subtracted from this value the result is:
-0.000001 < n/(x*x) - 1.0 < 0.00001
To be safe, terminate the loop when:
| n/(x*x) - 1.0 | < 0.00001
where |x| means the absolute value of x.
Is there a floating point absolute value instruction?