Yes, as long as the remaining bits are enough to specify the operation.

# Immediate Operand

OR Operation on Bits
first operand 0011
second operand 0101

result 0111

Some machine instructions use 16 of their 32 bits to hold one of the two operands. An operand that is directly encoded as part of a machine instruction is called an immediate operand. For example, here is one of the instructions from the previous example program:

```address         machine code      assembly code

0x00400000      0x34080002        ori \$8,\$0,0x2
```

The last 16 bits (four hex characters) of the machine instruction contain the operand 0x0002. (The assembly language instruction can just say "0x2"). The machine instruction tells the ALU to perform a bitwise OR between the contents of register `\$0` and the immediate operand 0x0002. The result is put in register `\$8` .

A bitwise operation is where a logical operation is performed on the bits of each column of the operands. Here is the bitwise OR between two 8-bit patterns:

```0110 1100    operand
0101 0110    operand
0111 1110    result
```

### QUESTION 2:

• What bit pattern is contained in register `\$0` ?
• How many bits are there in each MIPS instruction?