li $t2,-2 li $t1,4 ror $t0,$t1,$t2
What does $t0 hold after the sequence has executed?
$t1 starts out with this bit pattern:
0000 0000 0000 0000 0000 0000 0000 0100
Because $t2 holds a negative two,
the bits are rotated two positions left:
0000 0000 0000 0000 0000 0000 0001 0000
You have reached the end of this chapter. Unless your head is rotating, click on a subject to go to where it was discussed.